If ${\sum\limits_{i = 1}^{20} {\left( {\frac{{{}^{20}{C_{i - 1}}}}{{{}^{20}{C_i} + {}^{20}{C_{i - 1}}}}} \right)} ^3}\, = \frac{k}{{21}}$, then $k$ equals

  • [JEE MAIN 2019]
  • A

    $400$

  • B

    $50$

  • C

    $200$

  • D

    $100$

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